[HACKERS] [POC] hash partitioning - Mailing list pgsql-hackers
From | Yugo Nagata |
---|---|
Subject | [HACKERS] [POC] hash partitioning |
Date | |
Msg-id | 20170228233313.fc14d8b6.nagata@sraoss.co.jp Whole thread Raw |
Responses |
Re: [HACKERS] [POC] hash partitioning
Re: [HACKERS] [POC] hash partitioning Re: [HACKERS] [POC] hash partitioning Re: [HACKERS] [POC] hash partitioning Re: [HACKERS] [POC] hash partitioning |
List | pgsql-hackers |
Hi all, Now we have a declarative partitioning, but hash partitioning is not implemented yet. Attached is a POC patch to add the hash partitioning feature. I know we will need more discussions about the syntax and other specifications before going ahead the project, but I think this runnable code might help to discuss what and how we implement this. * Description In this patch, the hash partitioning implementation is basically based on the list partitioning mechanism. However, partition bounds cannot be specified explicitly, but this is used internally as hash partition index, which is calculated when a partition is created or attached. The tentative syntax to create a partitioned table is as bellow; CREATE TABLE h (i int) PARTITION BY HASH(i) PARTITIONS 3 USING hashint4; The number of partitions is specified by PARTITIONS, which is currently constant and cannot be changed, but I think this is needed to be changed in some manner. A hash function is specified by USING. Maybe, specifying hash function may be ommitted, and in this case, a default hash function corresponding to key type will be used. A partition table can be create as bellow; CREATE TABLE h1 PARTITION OF h; CREATE TABLE h2 PARTITION OF h; CREATE TABLE h3 PARTITION OF h; FOR VALUES clause cannot be used, and the partition bound is calclulated automatically as partition index of single integer value. When trying create partitions more than the number specified by PARTITIONS, it gets an error. postgres=# create table h4 partition of h; ERROR: cannot create hash partition more than 3 for h An inserted record is stored in a partition whose index equals abs(hashfunc(key)) % <number_of_partitions>. In the above example, this is abs(hashint4(i))%3. postgres=# insert into h (select generate_series(0,20)); INSERT 0 21 postgres=# select *,tableoid::regclass from h; i | tableoid ----+---------- 0 | h1 1 | h1 2 | h1 4 | h1 8 | h1 10 | h1 11 | h1 14 | h1 15 | h1 17 | h1 20 | h1 5 | h2 12 | h2 13 | h2 16 | h2 19 | h2 3 | h3 6 | h3 7 | h3 9 | h3 18 | h3 (21 rows) * Todo / discussions In this patch, we cannot change the number of partitions specified by PARTITIONS. I we can change this, the partitioning rule (<partition index> = abs(hashfunc(key)) % <number_of_partitions>) is also changed and then we need reallocatiing records between partitions. In this patch, user can specify a hash function USING. However, we migth need default hash functions which are useful and proper for hash partitioning. Currently, even when we issue SELECT query with a condition, postgres looks into all partitions regardless of each partition's constraint, because this is complicated such like "abs(hashint4(i))%3 = 0". postgres=# explain select * from h where i = 10; QUERY PLAN ---------------------------------------------------------- Append (cost=0.00..125.62 rows=40 width=4) -> Seq Scan on h (cost=0.00..0.00 rows=1 width=4) Filter: (i = 10) -> Seq Scan on h1 (cost=0.00..41.88 rows=13 width=4) Filter: (i = 10) -> Seq Scan on h2 (cost=0.00..41.88 rows=13 width=4) Filter: (i = 10) -> Seq Scan on h3 (cost=0.00..41.88 rows=13 width=4) Filter: (i = 10) (9 rows) However, if we modify a condition into a same expression as the partitions constraint, postgres can exclude unrelated table from search targets. So, we might avoid the problem by converting the qual properly before calling predicate_refuted_by(). postgres=# explain select * from h where abs(hashint4(i))%3 = abs(hashint4(10))%3; QUERY PLAN ---------------------------------------------------------- Append (cost=0.00..61.00 rows=14 width=4) -> Seq Scan on h (cost=0.00..0.00 rows=1 width=4) Filter: ((abs(hashint4(i)) % 3) = 2) -> Seq Scan on h3 (cost=0.00..61.00 rows=13 width=4) Filter: ((abs(hashint4(i)) % 3) = 2) (5 rows) Best regards, Yugo Nagata -- Yugo Nagata <nagata@sraoss.co.jp> -- Sent via pgsql-hackers mailing list (pgsql-hackers@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-hackers
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