On 2017-05-08 09:12:13 -0400, Tom Lane wrote:
> Simon Riggs <simon@2ndquadrant.com> writes:
> > So rearranged code a little to keep it lean.
>
> Didn't you break it with that? As it now stands, the memcpy will
> copy the nonzero value.
I've not seen a fix and/or alleviating comment about this so far. Did I
miss something?
- Andres