Re: Query about foreign key details for php framework - Mailing list pgsql-sql

From David Binney
Subject Re: Query about foreign key details for php framework
Date
Msg-id CAN123gkwOujiAO3pwLqtouitTi0ai1J75iF1tNgfx6Hrrxh-=w@mail.gmail.com
Whole thread
In response to Re: Query about foreign key details for php framework  (Adrian Klaver <adrian.klaver@aklaver.com>)
Responses Re: Query about foreign key details for php framework
List pgsql-sql
That is exactly the desired result, but in my db it is returning 2k rows with exactly the same query, even filtered to a specific table. 

On Sat, 27 Feb 2016 at 01:16 Adrian Klaver <adrian.klaver@aklaver.com> wrote:
On 02/25/2016 07:19 PM, David Binney wrote:
> Ah sorry adrian,
>
> I am a little in the dark as well since this is just a broken piece of
> ORM i am attempting to fix, in the framework. So, maybe if you could
> help to reproduce that select list as a start that would be great. But,
> I am suspecting they were trying to pull similar datasets from mysql or
> postgres as an end goal.
>

Alright I ran the Postgres query you provided and it threw an error:

ERROR:  missing FROM-clause entry for table "cu"
LINE 26:   cu.ordinal_position;

in the ORDER BY clause. Changing cu.ordinal_position to
kcu.ordinal_position obtained a result when run for a table in one of my
databases:

production=# select
   rc.constraint_name AS name,
   tc.constraint_type AS type,
   kcu.column_name,
   rc.match_option AS match_type,
   rc.update_rule AS on_update,
   rc.delete_rule AS on_delete,
   kcu.table_name AS references_table,
   kcu.column_name AS references_field,
   kcu.ordinal_position
FROM
   (select distinct * from information_schema.referential_constraints) rc
   JOIN information_schema.key_column_usage kcu
   ON  kcu.constraint_name   = rc.constraint_name
   AND kcu.constraint_schema = rc.constraint_schema
   JOIN information_schema.table_constraints tc ON tc.constraint_name =
rc.constraint_name
   AND tc.constraint_schema = rc.constraint_schema
   AND tc.constraint_name = rc.constraint_name
   AND tc.table_schema = rc.constraint_schema
WHERE
   kcu.table_name = 'projection'
   AND rc.constraint_schema = 'public'
   AND tc.constraint_type = 'FOREIGN KEY'
ORDER BY
   rc.constraint_name,
   kcu.ordinal_position;

-[ RECORD 1 ]----+------------
name             | con_fkey
type             | FOREIGN KEY
column_name      | c_id
match_type       | NONE
on_update        | CASCADE
on_delete        | CASCADE
references_table | projection
references_field | c_id
ordinal_position | 1
-[ RECORD 2 ]----+------------
name             | con_fkey
type             | FOREIGN KEY
column_name      | c_id
match_type       | NONE
on_update        | CASCADE
on_delete        | CASCADE
references_table | projection
references_field | c_id
ordinal_position | 1
-[ RECORD 3 ]----+------------
name             | pno_fkey
type             | FOREIGN KEY
column_name      | p_item_no
match_type       | NONE
on_update        | CASCADE
on_delete        | CASCADE
references_table | projection
references_field | p_item_no

If this is not the desired result, then we will need more information.

--
Adrian Klaver
adrian.klaver@aklaver.com
--
Cheers David Binney

pgsql-sql by date:

Previous
From: Adrian Klaver
Date:
Subject: Re: Query about foreign key details for php framework
Next
From: Desmond Coertzen
Date:
Subject: Re: Subselect left join / not exists()