Re: grouping subsets - Mailing list pgsql-sql
| From | Oliveiros d'Azevedo Cristina |
|---|---|
| Subject | Re: grouping subsets |
| Date | |
| Msg-id | 7A80C0C5124F4524BC664E4F6D29F76F@marktestcr.marktest.pt Whole thread Raw |
| In response to | grouping subsets (Rainer Stengele <rainer.stengele@diplan.de>) |
| Responses |
Re: grouping subsets
|
| List | pgsql-sql |
Yes. This is somewhat more complicated because it has more constraints. I've noticed that a given combination doesn't appear with holes on a certain day. For ex, on a daily basis, we have every three key combinations together. We dont have things like 2010-7-01 1726 3212 1428 2010-7-01 1726 3212 1428 ... 318 1846 1012 2010-7-01 1726 3212 1428 Can I assume that, for a certain day , the records for the same three combination are all together? There is just one set per day for a given combination? Or is it possible to have the same combination on one day with several sets? Best, Oliveiros ----- Original Message ----- From: "Rainer Stengele" <rainer.stengele@diplan.de> Newsgroups: gmane.comp.db.postgresql.sql To: "Oliveiros d'Azevedo Cristina" <oliveiros.cristina@marktest.pt> Cc: <> Sent: Thursday, July 29, 2010 10:41 AM Subject: Re: grouping subsets > Howdy Cristina, > > unfortunately things are more complicated. I have inserted an excerpt of > the real data here: > > ================================================================================ > TableID MasterID dtBegin dtEnd > idR idL idB consumption > 4057312 295530 2010-07-01 00:59:21.077 2010-07-01 > 01:32:59.670 1726 3212 1428 279 > 4061043 295574 2010-07-01 01:59:31.137 2010-07-01 > 02:32:09.373 1726 3212 1428 183 > 4083397 295838 2010-07-01 07:57:51.327 2010-07-01 > 08:28:28.117 318 1846 1012 30 > 4090858 295920 2010-07-01 09:52:33.777 2010-07-01 > 10:31:34.393 318 1846 1012 487 > 4094589 295961 2010-07-01 10:47:59.370 2010-07-01 > 11:32:20.903 318 1846 1012 472 > 4098330 296013 2010-07-01 11:58:53.890 2010-07-01 > 12:31:35.730 318 1846 1012 195 > 4102069 296058 2010-07-01 12:36:19.170 2010-07-01 > 13:32:13.950 318 1846 1012 338 > 4105809 296102 2010-07-01 13:58:53.170 2010-07-01 > 14:02:57.710 318 1846 1012 105 > 4109555 296150 2010-07-01 14:59:11.663 2010-07-01 > 15:32:33.810 318 1846 1012 187 > 4113305 296194 2010-07-01 15:59:01.797 2010-07-01 > 16:02:27.260 318 1846 1012 108 > 4117048 296238 2010-07-01 16:20:47.997 2010-07-01 > 17:32:49.367 318 1846 1012 179 > 4120791 296282 2010-07-01 17:58:27.657 2010-07-01 > 18:29:01.733 318 1846 1012 256 > 4128291 296370 2010-07-01 19:54:17.687 2010-07-01 > 20:32:53.850 318 1846 1012 239 > 4132044 296413 2010-07-01 20:31:37.653 2010-07-01 > 21:29:13.497 318 1846 1012 39 > 4135797 296458 2010-07-01 21:59:13.983 2010-07-01 > 22:32:46.503 318 1846 1012 157 > 4139572 296506 2010-07-01 22:58:49.530 2010-07-01 > 23:32:22.543 318 1846 1012 218 > 4142941 296554 2010-07-01 23:59:13.857 2010-07-02 > 00:32:30.390 318 1846 1012 248 > 4146289 296598 2010-07-02 00:58:55.763 2010-07-02 > 01:32:41.983 318 1846 1012 204 > 4149616 296642 2010-07-02 01:46:57.357 2010-07-02 > 02:32:56.983 318 1846 1012 42 > 4152952 296686 2010-07-02 02:55:19.653 2010-07-02 > 03:32:28.013 318 1846 1012 135 > 4156289 296730 2010-07-02 03:43:52.777 2010-07-02 > 04:32:55.250 318 1846 1012 743 > 4159624 296774 2010-07-02 04:43:15.310 2010-07-02 > 05:32:44.547 318 1846 1012 277 > 4162961 296817 2010-07-02 05:58:59.483 2010-07-02 > 06:32:37.340 318 1846 1012 121 > 4166303 296862 2010-07-02 06:58:50.733 2010-07-02 > 07:32:39.113 318 1846 1012 239 > 4172981 296950 2010-07-02 07:28:55.293 2010-07-02 > 09:33:01.200 318 1846 1012 512 > 4176322 296993 2010-07-02 09:59:04.607 2010-07-02 > 10:33:01.903 318 1846 1012 139 > 4179667 297038 2010-07-02 10:55:27.760 2010-07-02 > 11:32:56.560 318 1846 1012 722 > 4183012 297082 2010-07-02 11:59:33.650 2010-07-02 > 12:32:14.700 318 1846 1012 163 > 4186351 297126 2010-07-02 12:23:45.997 2010-07-02 > 13:32:59.500 318 1846 1012 284 > 4189689 297169 2010-07-02 13:44:21.253 2010-07-02 > 14:18:05.080 318 1846 1012 254 > 4196371 297258 2010-07-02 16:16:19.123 2010-07-02 > 16:32:53.437 1706 3541 1511 161 > 4199720 297301 2010-07-02 16:59:35.127 2010-07-02 > 17:32:57.950 1706 3541 1511 250 > 4203068 297346 2010-07-02 17:59:34.027 2010-07-02 > 18:32:54.337 1706 3541 1511 302 > 4206413 297389 2010-07-02 18:59:28.730 2010-07-02 > 19:32:37.950 1706 3541 1511 276 > 4209758 297434 2010-07-02 19:54:00.243 2010-07-02 > 20:32:57.433 1706 3541 1511 209 > 4213102 297473 2010-07-02 20:49:10.963 2010-07-02 > 21:30:44.540 1706 3541 1511 76 > 4216447 297511 2010-07-02 21:59:34.810 2010-07-02 > 22:33:00.603 1706 3541 1511 287 > 4219818 297569 2010-07-02 22:56:52.750 2010-07-02 > 23:59:31.607 1706 3541 1511 1877 > 4219819 297570 2010-07-02 23:59:21.577 2010-07-03 > 00:54:40.153 1706 3541 1511 1798 > 4219821 297572 2010-07-03 00:48:03.310 2010-07-03 > 01:59:37.920 1706 3541 1511 1125 > 4219823 297574 2010-07-03 01:51:01.057 2010-07-03 > 02:59:45.433 1706 3541 1511 1629 > 4219820 297571 2010-07-03 02:59:29.393 2010-07-03 > 03:59:54.920 1706 3541 1511 2462 > 4219822 297573 2010-07-03 03:59:18.663 2010-07-03 > 04:01:48.810 1706 3541 1511 70 > 4225738 297656 2010-07-03 06:13:34.980 2010-07-03 > 06:28:09.697 1726 3212 1428 46 > 4228694 297695 2010-07-03 06:59:15.560 2010-07-03 > 07:32:45.653 1726 3212 1428 251 > 4231649 297733 2010-07-03 07:59:11.937 2010-07-03 > 08:32:57.217 1726 3212 1428 284 > 4234604 297771 2010-07-03 08:57:00.357 2010-07-03 > 09:32:47.903 1726 3212 1428 227 > 4237559 297809 2010-07-03 09:59:19.813 2010-07-03 > 10:33:02.063 1726 3212 1428 285 > 4261156 298596 2010-07-04 22:59:09.863 2010-07-04 > 23:33:45.530 1726 3212 1428 1286 > 4264114 298646 2010-07-04 23:59:16.967 2010-07-05 > 00:33:08.107 1726 3212 1428 297 > 4267067 298690 2010-07-05 00:59:15.187 2010-07-05 > 01:32:48.300 1726 3212 1428 333 > 4270023 298734 2010-07-05 01:59:02.497 2010-07-05 > 02:32:48.780 1726 3212 1428 270 > 4272977 298778 2010-07-05 02:41:43.737 2010-07-05 > 03:32:56.043 1726 3212 1428 317 > 4275927 298822 2010-07-05 03:59:17.027 2010-07-05 > 04:33:14.947 1726 3212 1428 1623 > ================================================================================ > > Description: > 1. Column: some ID > 2. Column: reference to another table > 3. and 4. column: timestamp from/to of the item > 5. Column: ID R > 6. Column: ID L > 7. Column: ID B > 8. Column: Sum of components > > Requirement: > Sum over all components (from column 8) for each combination of ID R, ID > L, ID B, but (!) > rows with same keys (R,L,B) should be summed up only until the keys > change. > Do not sum up the components for identical keys, if there are other keys > between them. > > Example result: > > idR idL idB SUM > 1726 3212 1428 462 > 318 1846 1012 ... > 1706 3541 1511 ... > 1726 3212 1428 ... > > > Note that the first and last entry here has the same keys > > Maybe you find a similar monster SQL solving such a requirement. > Thanks for considering! > > Rainer > > > > Am 27.07.2010 12:37, schrieb Oliveiros d'Azevedo Cristina: >> Howdy, Rainer. >> >> It's been a while, so I don't know if you are still interested in this >> problem or if you, in the meantime, found yourself a solution, >> but I've tried this on a local copy of the example you provided and it >> seems to work. >> >> The problem is that I suspect that if you have several thousands of >> records on your table it will become slow... >> >> Best, >> Oliveiros >> >> SELECT SUM(tudo.parcela),tudo.a >> FROM >> ( >> SELECT fo.parcela,fo.a,fo.b,fo.c,MIN(th.c) as d >> FROM >> ( >> SELECT se.a as parcela,se.b as a,se.c as b, MAX(pr.c) as c >> FROM >> yourTable se >> LEFT JOIN >> ( >> SELECT a.* >> FROM yourTable a >> JOIN yourTable b >> ON (b.b <> a.b) >> AND ((age(a.c,b.c) = '1 day'::interval) >> >> ) >> ) pr >> ON pr.b = se.b >> AND se.c >= pr.c >> GROUP BY se.a,se.b,se.c >> ) fo >> LEFT JOIN >> ( >> SELECT a.* >> FROM yourTable a >> JOIN yourTable b >> ON (b.b <> a.b) >> AND ((age(a.c,b.c) = '-1 day'::interval) >> ) >> ) th >> ON fo.a = th.b >> AND fo.b <= th.c >> GROUP BY fo.parcela,fo.a,fo.b,fo.c >> ) tudo >> GROUP BY tudo.a,tudo.c,tudo.d >> >> >> >> >> To: <pgsql-sql@postgresql.org> >> Sent: Thursday, July 22, 2010 9:09 AM >> Subject: [SQL] grouping subsets >> >> >>> Hi, >>> >>> having a table similar to >>> >>> | 1 | B | [2010-07-15 Do] | >>> | 1 | B | [2010-07-16 Fr] | >>> |---+---+-----------------| >>> | 2 | C | [2010-07-17 Sa] | >>> | 2 | C | [2010-07-18 So] | >>> |---+---+-----------------| >>> | 1 | B | [2010-07-19 Mo] | >>> | 1 | B | [2010-07-20 Di] | >>> | 1 | B | [2010-07-21 Mi] | >>> | 1 | B | [2010-07-22 Do] | >>> |---+---+-----------------| >>> | 3 | D | [2010-07-23 Fr] | >>> >>> a simple group by gives me: >>> >>> | 6 | B | >>> | 4 | C | >>> | 3 | D | >>> >>> >>> What I want to get is the values grouped by "subset", where a subset is >>> a set of rows with identical column until the colum changes. >>> Is there a way to get >>> >>> | 2 | B | >>> | 4 | C | >>> | 4 | B | >>> | 3 | D | >>> >>> by SQL only? >>> >>> - Rainer >>> >>> >>> >>> >>> >>> -- >>> Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) >>> To make changes to your subscription: >>> http://www.postgresql.org/mailpref/pgsql-sql >> >>