Re: GROUPING SETS and SQL standard - Mailing list pgsql-hackers
From | Pavel Stehule |
---|---|
Subject | Re: GROUPING SETS and SQL standard |
Date | |
Msg-id | CAFj8pRB14bsm1Hf50OMkqbp17nZCvokbo5M3Q=-Ji0TVaG1MPQ@mail.gmail.com Whole thread Raw |
In response to | GROUPING SETS and SQL standard (Phil Florent <philflorent@hotmail.com>) |
Responses |
RE: GROUPING SETS and SQL standard
|
List | pgsql-hackers |
Hi,We are still on the process to migrate our applications from proprietary RDBMS to PostgreSQL.Here is a simple query executed on various systems (real query is different but this one does not need any data) :Connected to:
Oracle Database 19c Standard Edition 2 Release 19.0.0.0.0 - Production
Version 19.3.0.0.0
SQL> select count(*) from (select 1 from dual where 0=1 group by grouping sets(())) tmp;
COUNT(*)
----------
0
select @@version;
GO
--------------------------------------------------------------------------------------------------------------------------- --------------------------------------------------------------------------------------------------------------------------- ------------------------------------------------------
Microsoft SQL Server 2017 (RTM-CU16) (KB4508218) - 14.0.3223.3 (X64)
Jul 12 2019 17:43:08
Copyright (C) 2017 Microsoft Corporation
Developer Edition (64-bit) on Linux (Ubuntu 16.04.6 LTS)
select count(*) from (select 1 as c1 where 0=1 group by grouping sets(())) tmp;
GO
-----------
0
(1 rows affected)
select version();
version
----------------------------------------------------------------------------------------------------------------
PostgreSQL 11.5 (Debian 11.5-1+deb10u1) on x86_64-pc-linux-gnu, compiled by gcc (Debian 8.3.0-6) 8.3.0, 64-bit
select count(*) from (select 1 from dual where 0=1 group by grouping sets(())) tmp;
count
-------
1
(1 ligne)
0 or 1, which behaviour conforms to the SQL standard ? We have a workaround and it's just informational.
┌──────────┬───────┐
│ ?column? │ count │
╞══════════╪═══════╡
│ 1 │ 1 │
└──────────┴───────┘
(1 row)
postgres=# select 1, count(*) from dual where false group by grouping sets(());
┌──────────┬───────┐
│ ?column? │ count │
╞══════════╪═══════╡
│ 1 │ 0 │
└──────────┴───────┘
(1 row)
Regards,
Phil
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