Thread: sql statement how to do ?
Hello everybody I have a question regarding an sql statement. I need to insert a new record into the table auftrag that is the almost the same as an existing record. In a similar situation i I use INSERT INTO auftrag_archiv (SELECT * FROM auftrag where a_id = '12345'); Now I need to do the following : INSERT INTO auftrag (SELECT * FROM auftrag where a_id = '12345'); The problem is, that the table auftrag has a primay key called pk_auftrag. Do this I get an error regarding duplicate pk_auftrag. Is there a way to spare pk_auftrag somehow ? Thanks in advance ... jr __________________________________________________ PFISTER + PARTNER, SYSTEM - ENGINEERING AG Juerg Rietmann Grundstrasse 22a 6343 Rotkreuz Switzerland internet : www.pup.ch phone : +4141 790 4040 fax : +4141 790 2545 mobile : +4179 211 0315 __________________________________________________
On Fri, 5 Jul 2002 09:03:38 +0000 (UTC), juerg.rietmann@pup.ch wrote: >INSERT INTO auftrag (SELECT * FROM auftrag where a_id = '12345'); > >The problem is, that the table auftrag has a primay key called pk_auftrag. >Do this I get an error regarding duplicate pk_auftrag. Is there a way to >spare pk_auftrag somehow ? Juerg, is a_id your primary key? My examples are based on this assumption, but if it is not, you still get the point, which is: You can't use SELECT * here. If you know the new a_id in advance: INSERT INTO auftrag (a_id, col2, col3, ...) SELECT '67890', col2, col3, ... FROM auftrag WHERE a_id = '12345'; If a_id is a serial or in any other way supplied automatically by a DEFAULT clause or a trigger: INSERT INTO auftrag (col2, col3, ...) SELECT col2, col3, ... FROM auftrag WHERE a_id = '12345'; HTH. ServusManfred