Thread: SQL question....
.... assuming the following schema: create table access (name text, address ip) I want to construct a SELECT statement which will return ONLY tuples containing IP and name pairs IF there is an IP that has two or more NAMEs associated with it. I've not figured out how to do this; I can get a list of all IPs and names ordered by IP, which I could then parse with a different program (e.g. "Select name, address from access order by address"), but the idea of course is to do it with one SELECT statement and return only rows that have multiple names listed for a given IP. -- Karl Denninger (karl@denninger.net) http://www.denninger.net
> create table access (name text, address ip)
>
> I want to construct a SELECT statement which will return ONLY tuples
> containing IP and name pairs IF there is an IP that has two or more
> NAMEs associated with it.
>
>
many ways:
select a1.* from access a1 where exists( select 1 from access a2 where a2.name=a2.name and a1.ip!=a2.ip );
select a1.*
from access a1
join access a2 using( name )
where a1.ip != a2.ip;
chester c young wrote: <blockquote cite="mid:624694.72418.qm@web54303.mail.re2.yahoo.com" type="cite"><blockquote type="cite"><prewrap="">create table access (name text, address ip) I want to construct a SELECT statement which will return ONLY tuples containing IP and name pairs IF there is an IP that has two or more NAMEs associated with it. </pre></blockquote><pre wrap=""> many ways: select a1.* from access a1 where exists( select 1 from access a2 where a2.name=a2.name and a1.ip!=a2.ip ); select a1.* from access a1 join access a2 using( name ) where a1.ip != a2.ip; </pre></blockquote> Those will return single entries as well (which is easy to do with an "ORDER BY", that is computationallysimpler)<br /><br /> What I want (and can't figure out) is a SELECT that returns ONLY tuples with two or moreNAME entries that have the same IP.<br /><br /> -- Karl<br />
I think this is what you're looking for:<br /><br />SELECT * FROM access <br /> WHERE ip IN(SELECT ip FROM access <br /> GROUP BY ip HAVING count(*) > 1)<br /><br /><div class="gmail_quote">On Tue, May 20, 2008 at 3:17 PM, Karl Denninger<<a href="mailto:karl@denninger.net">karl@denninger.net</a>> wrote:<br /><blockquote class="gmail_quote" style="border-left:1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;"><div bgcolor="#ffffff" text="#000000">chester c young wrote: <blockquote type="cite"><blockquote type="cite"><pre>create table access (name text,address ip) I want to construct a SELECT statement which will return ONLY tuples containing IP and name pairs IF there is an IP that has two or more NAMEs associated with it. </pre></blockquote><pre>many ways: select a1.* from access a1 where exists( select 1 from access a2 where <a href="http://a2.name" target="_blank">a2.name</a>=<ahref="http://a2.name" target="_blank">a2.name</a> and a1.ip!=a2.ip ); select a1.* from access a1 join access a2 using( name ) where a1.ip != a2.ip; </pre></blockquote> Those will return single entries as well (which is easy to do with an "ORDER BY", that is computationallysimpler)<br /><br /> What I want (and can't figure out) is a SELECT that returns ONLY tuples with two or moreNAME entries that have the same IP.<br /><br /> -- Karl<br /></div></blockquote></div><br />
On Tue, May 20, 2008 at 11:44 PM, Karl Denninger <karl@denninger.net> wrote:
try this:
select ip, name from access where ip in ( select ip from access group by ip having count(name) > 2);
heven't execued it, so may need some coaxing. Let me know the results.
Best regards,
--
gurjeet[.singh]@EnterpriseDB.com
singh.gurjeet@{ gmail | hotmail | indiatimes | yahoo }.com
EnterpriseDB http://www.enterprisedb.com
Mail sent from my BlackLaptop device
.... assuming the following schema:
create table access (name text, address ip)
I want to construct a SELECT statement which will return ONLY tuples containing IP and name pairs IF there is an IP that has two or more NAMEs associated with it.
I've not figured out how to do this; I can get a list of all IPs and names ordered by IP, which I could then parse with a different program (e.g. "Select name, address from access order by address"), but the idea of course is to do it with one SELECT statement and return only rows that have multiple names listed for a given IP.
try this:
select ip, name from access where ip in ( select ip from access group by ip having count(name) > 2);
heven't execued it, so may need some coaxing. Let me know the results.
Best regards,
gurjeet[.singh]@EnterpriseDB.com
singh.gurjeet@{ gmail | hotmail | indiatimes | yahoo }.com
EnterpriseDB http://www.enterprisedb.com
Mail sent from my BlackLaptop device
Gurjeet Singh wrote: > On Tue, May 20, 2008 at 11:44 PM, Karl Denninger <karl@denninger.net > <mailto:karl@denninger.net>> wrote: > > .... assuming the following schema: > > create table access (name text, address ip) > > I want to construct a SELECT statement which will return ONLY > tuples containing IP and name pairs IF there is an IP that has two > or more NAMEs associated with it. > > I've not figured out how to do this; I can get a list of all IPs > and names ordered by IP, which I could then parse with a different > program (e.g. "Select name, address from access order by > address"), but the idea of course is to do it with one SELECT > statement and return only rows that have multiple names listed for > a given IP. > > > try this: > > select ip, name from access where ip in ( select ip from access group > by ip having count(name) > 2); > > heven't execued it, so may need some coaxing. Let me know the results. > > Best regards, > -- > A small modification got CLOSE.... I can live with that set of results..... I think. Thanks :)
On Wed, May 21, 2008 at 4:47 AM, Karl Denninger <karl@denninger.net> wrote:
I am glad.
Harold had posted almost identical solution one hour before I did (I had the mail ready to be sent almost after you posted, but lost power and network connection for about an hour).
Can you please post your modified query, for the record; we might still be able to get you _exactly_ what you want.
Best regards,
--
gurjeet[.singh]@EnterpriseDB.com
singh.gurjeet@{ gmail | hotmail | indiatimes | yahoo }.com
EnterpriseDB http://www.enterprisedb.com
Mail sent from my BlackLaptop device
Gurjeet Singh wrote:A small modification got CLOSE.... I can live with that set of results..... I think.On Tue, May 20, 2008 at 11:44 PM, Karl Denninger <karl@denninger.net <mailto:karl@denninger.net>> wrote:
.... assuming the following schema:
create table access (name text, address ip)
I want to construct a SELECT statement which will return ONLY
tuples containing IP and name pairs IF there is an IP that has two
or more NAMEs associated with it.
I've not figured out how to do this; I can get a list of all IPs
and names ordered by IP, which I could then parse with a different
program (e.g. "Select name, address from access order by
address"), but the idea of course is to do it with one SELECT
statement and return only rows that have multiple names listed for
a given IP.
try this:
select ip, name from access where ip in ( select ip from access group by ip having count(name) > 2);
heven't execued it, so may need some coaxing. Let me know the results.
Best regards,
--
I am glad.
Harold had posted almost identical solution one hour before I did (I had the mail ready to be sent almost after you posted, but lost power and network connection for about an hour).
Can you please post your modified query, for the record; we might still be able to get you _exactly_ what you want.
Best regards,
--
gurjeet[.singh]@EnterpriseDB.com
singh.gurjeet@{ gmail | hotmail | indiatimes | yahoo }.com
EnterpriseDB http://www.enterprisedb.com
Mail sent from my BlackLaptop device
Gurjeet Singh wrote:
On Wed, May 21, 2008 at 4:47 AM, Karl Denninger <karl@denninger.net> wrote:I used an "order by" and also increased the count to "> 2" because there are a lot of blank "name" records in there as well (but I don't want to select on those; as an artifact of how the system works there will usually be a blank name entry for most IP corresponding entries, but not all)Gurjeet Singh wrote:A small modification got CLOSE.... I can live with that set of results..... I think.On Tue, May 20, 2008 at 11:44 PM, Karl Denninger <karl@denninger.net <mailto:karl@denninger.net>> wrote:
.... assuming the following schema:
create table access (name text, address ip)
I want to construct a SELECT statement which will return ONLY
tuples containing IP and name pairs IF there is an IP that has two
or more NAMEs associated with it.
I've not figured out how to do this; I can get a list of all IPs
and names ordered by IP, which I could then parse with a different
program (e.g. "Select name, address from access order by
address"), but the idea of course is to do it with one SELECT
statement and return only rows that have multiple names listed for
a given IP.
try this:
select ip, name from access where ip in ( select ip from access group by ip having count(name) > 2);
heven't execued it, so may need some coaxing. Let me know the results.
Best regards,
--
I am glad.
Harold had posted almost identical solution one hour before I did (I had the mail ready to be sent almost after you posted, but lost power and network connection for about an hour).
Can you please post your modified query, for the record; we might still be able to get you _exactly_ what you want.
Best regards,
Karl Denninger (karl@denninger.net) http://www.denninger.net
On Wed, May 21, 2008 at 8:33 AM, Karl Denninger <karl@denninger.net> wrote:
You can add a filter to the subquery using
WHERE name <> ''
Also, if you don't have it already, you may create an index on IP column for better performance.
--
gurjeet[.singh]@EnterpriseDB.com
singh.gurjeet@{ gmail | hotmail | indiatimes | yahoo }.com
EnterpriseDB http://www.enterprisedb.com
Mail sent from my BlackLaptop device
Gurjeet Singh wrote:I used an "order by" and also increased the count to "> 2" because there are a lot of blank "name" records in there as well (but I don't want to select on those; as an artifact of how the system works there will usually be a blank name entry for most IP corresponding entries, but not all)On Wed, May 21, 2008 at 4:47 AM, Karl Denninger <karl@denninger.net> wrote:Gurjeet Singh wrote:A small modification got CLOSE.... I can live with that set of results..... I think.On Tue, May 20, 2008 at 11:44 PM, Karl Denninger <karl@denninger.net <mailto:karl@denninger.net>> wrote:
.... assuming the following schema:
create table access (name text, address ip)
I want to construct a SELECT statement which will return ONLY
tuples containing IP and name pairs IF there is an IP that has two
or more NAMEs associated with it.
I've not figured out how to do this; I can get a list of all IPs
and names ordered by IP, which I could then parse with a different
program (e.g. "Select name, address from access order by
address"), but the idea of course is to do it with one SELECT
statement and return only rows that have multiple names listed for
a given IP.
try this:
select ip, name from access where ip in ( select ip from access group by ip having count(name) > 2);
heven't execued it, so may need some coaxing. Let me know the results.
Best regards,
--
I am glad.
Harold had posted almost identical solution one hour before I did (I had the mail ready to be sent almost after you posted, but lost power and network connection for about an hour).
Can you please post your modified query, for the record; we might still be able to get you _exactly_ what you want.
Best regards,
You can add a filter to the subquery using
WHERE name <> ''
Also, if you don't have it already, you may create an index on IP column for better performance.
--
gurjeet[.singh]@EnterpriseDB.com
singh.gurjeet@{ gmail | hotmail | indiatimes | yahoo }.com
EnterpriseDB http://www.enterprisedb.com
Mail sent from my BlackLaptop device
Gurjeet Singh wrote: > On Wed, May 21, 2008 at 8:33 AM, Karl Denninger <karl@denninger.net > <mailto:karl@denninger.net>> wrote: > > Gurjeet Singh wrote: >> On Wed, May 21, 2008 at 4:47 AM, Karl Denninger >> <karl@denninger.net <mailto:karl@denninger.net>> wrote: >> >> Gurjeet Singh wrote: >> >> On Tue, May 20, 2008 at 11:44 PM, Karl Denninger >> <karl@denninger.net <mailto:karl@denninger.net> >> <mailto:karl@denninger.net <mailto:karl@denninger.net>>> >> wrote: >> >> .... assuming the following schema: >> >> create table access (name text, address ip) >> >> I want to construct a SELECT statement which will >> return ONLY >> tuples containing IP and name pairs IF there is an IP >> that has two >> or more NAMEs associated with it. >> >> I've not figured out how to do this; I can get a list >> of all IPs >> and names ordered by IP, which I could then parse with >> a different >> program (e.g. "Select name, address from access order by >> address"), but the idea of course is to do it with one >> SELECT >> statement and return only rows that have multiple >> names listed for >> a given IP. >> >> >> try this: >> >> select ip, name from access where ip in ( select ip from >> access group by ip having count(name) > 2); >> >> heven't execued it, so may need some coaxing. Let me know >> the results. >> >> Best regards, >> -- >> >> A small modification got CLOSE.... I can live with that set >> of results..... I think. >> >> >> I am glad. >> >> Harold had posted almost identical solution one hour before I did >> (I had the mail ready to be sent almost after you posted, but >> lost power and network connection for about an hour). >> >> Can you please post your modified query, for the record; we might >> still be able to get you _exactly_ what you want. >> >> Best regards, >> >> >> > I used an "order by" and also increased the count to "> 2" because > there are a lot of blank "name" records in there as well (but I > don't want to select on those; as an artifact of how the system > works there will usually be a blank name entry for most IP > corresponding entries, but not all) > > > You can add a filter to the subquery using > > WHERE name <> '' > > Also, if you don't have it already, you may create an index on IP > column for better performance. > Mail sent from my BlackLaptop device Its a very large table and is indexed already... Karl Denninger (karl@denninger.net) http://www.denninger.net
At 12:20 PM 5/21/2008, pgsql-sql-owner@postgresql.org wrote: >Date: Wed, 21 May 2008 06:39:11 -0500 >From: Karl Denninger <karl@denninger.net> >To: Gurjeet Singh <singh.gurjeet@gmail.com> >Cc: pgsql-sql@postgresql.org >Subject: Re: SQL question.... >Message-ID: <483409DF.7050905@denninger.net> > > > Also, if you don't have it already, you may create an index on IP > > column for better performance. > > Mail sent from my BlackLaptop device >Its a very large table and is indexed already... Not to completely beat this thing to death, but are you using an inet or other custom datatype for this? I think if you index ip's using a custom data type and search/group for specific octets, you'll get much better performance than just searching via a regular b-tree string index.. http://www.postgresql.org/docs/8.3/static/datatype-net-types.html Steve
Steve Midgley wrote: > At 12:20 PM 5/21/2008, pgsql-sql-owner@postgresql.org wrote: >> Date: Wed, 21 May 2008 06:39:11 -0500 >> From: Karl Denninger <karl@denninger.net> >> To: Gurjeet Singh <singh.gurjeet@gmail.com> >> Cc: pgsql-sql@postgresql.org >> Subject: Re: SQL question.... >> Message-ID: <483409DF.7050905@denninger.net> >> >> > Also, if you don't have it already, you may create an index on IP >> > column for better performance. >> > Mail sent from my BlackLaptop device >> Its a very large table and is indexed already... > > Not to completely beat this thing to death, but are you using an inet > or other custom datatype for this? I think if you index ip's using a > custom data type and search/group for specific octets, you'll get much > better performance than just searching via a regular b-tree string > index.. > > http://www.postgresql.org/docs/8.3/static/datatype-net-types.html > > Steve > I'm using Inet but the searches/replaces that need to be done are all done on the full address. In this case it doesn't do a bit of good because the entire table has to be sequential scanned. Karl Denninger (karl@denninger.net) http://www.denninger.net